eg:
$url=http://www.example.com/.
how to make the $url to this style.
http://test.google.com/example.com in php?
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4 Answers
Comments
$url_parts=parse_url($url);
echo $url="http://test.google.com/".str_replace('www.','',$url_parts['host']);
5 Comments
Joshua - Pendo
Damn, I obviously did too much than needed!
zhuanzhou
if the url is test.google.com/example.com. can i still get the result as this.test.google.com/example.com
Shakti Singh
@zhuanzhou:Then you do not need conversion at all. Check host before applying conversation if it is
test.google.com. you do not need conversion.zhuanzhou
but i must chect it? this is input by the editor. how to check it if has the test.google.com in the url?
Shakti Singh
after applying
parse_url you can if ($url_parts['host'] == 'test.google.com')$url = "http://www.example.com";
$Step1 = str_replace(array("http://", "https://", "www."), "", $url);
$Step2 = explode("/", $Step1);
$newUrl = "http://test.google.com/".$Step2[0];
Basically what I did is replacing any http://, https:// and www. strings from the URL in $url and replace them with a blank string. Then I explode the result of this replace on an '/' character, because there might be an URL given as http://www.test.com/mydir/ so we lose the mydir. If this isn't want you need, skip step 2 and replace $Step2[0] with $Step1 on the last line.
This last line adds the URL you want in $newUrl
Comments
Try this:
$url = "http://www.example.com/";
$url = preg_replace("/(?:http:\/\/)?(?:www\.)?([a-z\d-\.]+)\/.*/", "http://test.google.com/$1", $url);
2 Comments
Jan Hančič
Please post your answer here, don't just link to some XYZ site
Volodymyr Bryliant
Sorry, i just new in stackoverflow, and only learn code syntax