doesn't java follow implicit type conversion?

Question

I was solving the following problem on Hacker rank. The program is supposed to print "Weird" onto the screen when N is odd. I checked the condition for N to be odd with the bitwise and(&) operator. But, I was getting this message from the compiler. I recently switched to java from c++. This operation works in C++. I wonder why it's not supported by java.

public class Solution {
private static final Scanner scanner = new Scanner(System.in);

public static void main(String[] args) {
    int N = scanner.nextInt();
    if(N&1){
        System.out.println("Weird");
    }
    else if(N>=2&&N<=5)
    {
       System.out.println("Not Weird"); 
    }
    else if(N>=6&&N<=20){
        System.out.println("Weird");
    }
    else{
        System.out.println("Not Weird");
    }

    scanner.close();
}

}

FYI: Adding spaces makes the code more readable, e.g. else if (N >= 2 && N <= 5) — Andreas
– Andreas, Commented Feb 17, 2020 at 17:48
@Michael At least CamelCase your ScriptioContinua; QUIDQUIDLATINEDICTUMSITALTUMSONATUR. — Elliott Frisch
– Elliott Frisch, Commented Feb 17, 2020 at 18:14

Elliott Frisch · Accepted Answer · 2020-02-17 17:43:33Z

5

Java is not C, you can't coerce an int to a boolean. This

if(N&1){

should be

if ((N & 1) == 1) {

edited Feb 17, 2020 at 17:43

answered Feb 17, 2020 at 17:42

Elliott Frisch

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2 Comments

Andreas Over a year ago

Personally, I would bold, highlight, super-size, etc. the first 4 words, and make it blink in a whole rainbow of neon colors. But that's just me being old and cranky.

Elliott Frisch Over a year ago

@Andreas Something like J͠a͠v͠a͠ ͠i͠s͠ ͠n͠o͠t͠ ͠C͠ .

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