Java to XML using JAXB

Question

I´m using JAXB to marshall an Java object to XML.

I want to make a web service where i put this code and return the xml, but the last line where i do the marshall doesn´t return a string because it´s a handler.

    JAXBContext context = JAXBContext.newInstance(Person.class);
    Marshaller marshaller = context.createMarshaller();
    marshaller.setProperty(Marshaller.JAXB_FORMATTED_OUTPUT, true);

    Person person = new Person("Anonymous", 32, "employee");    

    marshaller.marshal(person, System.out);

Has anyone done this before?

Kal · Accepted Answer · 2011-05-18 22:04:23Z

1

The marshaller.marshal() has several overriden methods that allow you to marshal an object into an outputstream, File, w3c.dom.Node ... etc.

The better question might be what are you using to write the web service. If you are using JAX-WS, these things are done automatically for you.

http://jaxb.java.net/nonav/2.2.3/docs/api/javax/xml/bind/Marshaller.html

answered May 18, 2011 at 22:04

Kal

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2 Comments

bruno Over a year ago

Yes its JAX-WS so, i´m gonna have a look at it.

bruno Over a year ago

The webservice doesn´t return the Java Object marshalled into XML. Returns this:<soap:Envelope> − <soap:Body> − <ns2:ConverteResponse> <return>Webservice JAXB</return> </ns2:ConverteResponse> </soap:Body> </soap:Envelope>

bdoughan · Accepted Answer · 2011-05-18 21:55:50Z

1

You could marshal to a StringWriter instead.

answered May 18, 2011 at 21:55

bdoughan

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1 Comment

bdoughan Over a year ago

@bruno - StringWriter is an implementation of Writer.

Community · Accepted Answer · 2017-05-23 12:27:56Z

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Just a comment, JAXBContext.newInstance needs to be cached, as it can be very expensive.

http://app-inf.blogspot.com/2012/10/performance-tuning-logging-right-way.html

How do I improve performance of application that uses the JAXBContext.newInstance operation?

edited May 23, 2017 at 12:27

CommunityBot

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answered Oct 11, 2012 at 16:55

user1738754

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