How do I invert the colours of the background image using CSS?

Question

I want to invert the colours of the background image given below.

html {
  background-image: url('data:image/svg+xml,%3Csvg width="64" height="64" viewBox="0 0 64 64" xmlns="http://www.w3.org/2000/svg"%3E%3Cpath d="M8 16c4.418 0 8-3.582 8-8s-3.582-8-8-8-8 3.582-8 8 3.582 8 8 8zm0-2c3.314 0 6-2.686 6-6s-2.686-6-6-6-6 2.686-6 6 2.686 6 6 6zm33.414-6l5.95-5.95L45.95.636 40 6.586 34.05.636 32.636 2.05 38.586 8l-5.95 5.95 1.414 1.414L40 9.414l5.95 5.95 1.414-1.414L41.414 8zM40 48c4.418 0 8-3.582 8-8s-3.582-8-8-8-8 3.582-8 8 3.582 8 8 8zm0-2c3.314 0 6-2.686 6-6s-2.686-6-6-6-6 2.686-6 6 2.686 6 6 6zM9.414 40l5.95-5.95-1.414-1.414L8 38.586l-5.95-5.95L.636 34.05 6.586 40l-5.95 5.95 1.414 1.414L8 41.414l5.95 5.95 1.414-1.414L9.414 40z" fill="%239C92AC" fill-opacity="0.4" fill-rule="evenodd"/%3E%3C/svg%3E');
}

davidwalsh.name/invert-colors-css Does it help?

User123
– User123

2020-03-09 15:29:03 +00:00
Commented Mar 9, 2020 at 15:29 — User123
– User123, Commented Mar 9, 2020 at 15:29

Temani Afif · Accepted Answer · 2020-03-09 15:31:35Z

Apply the coloration to the background and use white color for SVG. You don't really need transparency since you are dealing with the html element so there is nothing behind.

html {
  background: url('data:image/svg+xml,%3Csvg width="64" height="64" viewBox="0 0 64 64" xmlns="http://www.w3.org/2000/svg"%3E%3Cpath d="M8 16c4.418 0 8-3.582 8-8s-3.582-8-8-8-8 3.582-8 8 3.582 8 8 8zm0-2c3.314 0 6-2.686 6-6s-2.686-6-6-6-6 2.686-6 6 2.686 6 6 6zm33.414-6l5.95-5.95L45.95.636 40 6.586 34.05.636 32.636 2.05 38.586 8l-5.95 5.95 1.414 1.414L40 9.414l5.95 5.95 1.414-1.414L41.414 8zM40 48c4.418 0 8-3.582 8-8s-3.582-8-8-8-8 3.582-8 8 3.582 8 8 8zm0-2c3.314 0 6-2.686 6-6s-2.686-6-6-6-6 2.686-6 6 2.686 6 6 6zM9.414 40l5.95-5.95-1.414-1.414L8 38.586l-5.95-5.95L.636 34.05 6.586 40l-5.95 5.95 1.414 1.414L8 41.414l5.95 5.95 1.414-1.414L9.414 40z" fill="white" fill-rule="evenodd"/%3E%3C/svg%3E'),
  rgba(156, 146, 172, 0.4);
}

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