Array is not getting printed in Java

Question

I want to print an array of size n, where each element is pow(i,i),i ranging from 1 to n. i.e. if I input n = 4, it should return me an array A = {1, 4, 27, 256}. This is because power(1,1) = 1, power(2,2) = 4, power(3,3) = 27 and power(4,4) = 256.

But, when I try to run the below code, it is not giving any output.

import java.io.*;
import java.util.*;
import java.lang.Math;

public class Main
{
public static void main(String[] args) 
{
    Main s = new Main();
    Scanner sc = new Scanner(System.in);
    int n = sc.nextInt();
    double[] A = new double[n];
    int j ;
    for(j = 0; j <= n; j++)
    {
        A[j] = Math.pow(j+1, j+1);
        //System.out.println(A[j]); --> 1
    }
    System.out.print(A);
    System.out.println(A);  //-->2
    for (int i=0; i<A.length; i++) 
    {
        System.out.print(A[i]+" "); // --> 3
    }
}
}

When I try to remove commented quotes for equation 1, it is printing me the values. But neither of equation 2 or 3 is helping me to print the array.

you have an ArrayIndexOutOfBoundsException. change for-loop to for(j = 0; j < n; j++). To print the result you can use System.out.println(Arrays.toString(A)); — falknis
– falknis, Commented Mar 14, 2020 at 9:46

Thakkar Darshan · Accepted Answer · 2020-03-14 10:57:38Z

2

Try This :-

 public static void main(String[] args) {
        Main s = new Main();
        Scanner sc = new Scanner(System.in);
        int n = sc.nextInt();
        double[] A = new double[n];
        int j ;
        for(j = 0; j <= n-1; j++)
        {
            A[j] = Math.pow(j+1, j+1);
            //System.out.println(A[j]); --> 1
        }
        System.out.print(A);
        System.out.println(A);  //-->2
        for (int i=0; i<A.length-1; i++)
        {
            System.out.print(A[i]+" "); // --> 3
        }
    }

answered Mar 14, 2020 at 10:57

Thakkar Darshan

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Comments

Ajay Venkata Raju · Accepted Answer · 2020-03-14 10:48:04Z

0

try this:

import java.io.*;
import java.util.*;
import java.lang.Math;

public class Main
{
public static void main(String[] args) 
{
    Main s = new Main();
    Scanner sc = new Scanner(System.in);
    int n = sc.nextInt();
    double[] A = new double[n];
    int j ;
    for(j = 1; j <= n; j++)
    {
        A[j-1] = Math.pow(j, j);
        //System.out.println(A[j]); //--> 1
    }
    System.out.print(A);
    System.out.println(A);  //-->2
    for (int i=0; i<A.length; i++) 
    {
        System.out.print(A[i]+" "); // --> 3
    }
}
}

answered Mar 14, 2020 at 10:48

Ajay Venkata Raju

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Comments

shakhawat · Accepted Answer · 2020-03-14 10:55:53Z

Instead of j <= n;, the loop condition should be j < n because the index start from 0 and ends at n - 1. If you try to access A[n], it will throw array index out of exception.

import java.io.*;
import java.util.*;
import java.lang.Math;

public class Main {

    public static void main(String[] args) {
        Main s = new Main();
        Scanner sc = new Scanner(System.in);
        int n = sc.nextInt();
        double[] A = new double[n];
        int j;
        for (j = 0; j < n; j++) {
            A[j] = Math.pow(j + 1, j + 1);
            //System.out.println(A[j]); --> 1
        }
        System.out.print(A);
        System.out.println(A);  //-->2
        for (int i = 0; i < A.length; i++) {
            System.out.print(A[i] + " "); // --> 3
        }
    }
}

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