T-SQL ORDER BY custom sorting

Question

Having IDs in range (-12 to 700, no 0).

I want to output a table sorted by IDs with IDs 1 to 700 coming first and then from -1 to -12.

Avoiding dealing with unions and splitting the sets by >0 and <0, is there a way to sort it like I want?

Thom A · Accepted Answer · 2020-03-30 11:46:18Z

5

Couple of CASE expressions would do this:

ORDER BY CASE WHEN YourColumn > 0 THEN 1 ELSE 2 END ASC,
         CASE WHEN YourColumn > 0 THEN YourColumn END ASC,
         YourColumn DESC; --As already inferred it is now less than 0

DB<>Fiddle

answered Mar 30, 2020 at 11:46

Thom A♦

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