Appending a string with a php function [duplicate]

Question

I'm trying to write a function which appends a string to an existing string for error handling.

The output that I'm searching:

// Begin:
// message1
// message2

Currently I have:

$error = "Begin:";

function addError($message) {
    $error .= "<br>" . $message;
}

addError("message1");
addError("message2");

echo $error;

// ----- Which outputs -----
// Begin:

I would assume that the code above does the same as:

$error = "Begin:";

$error .= "<br>" . "message1";
$error .= "<br>" . "message2";

echo $error;

// ----- Which outputs -----
// Begin:
// message1
// message2

But it doesn't seem to work. Could someone elaborate on the mistake(s) I'm making?

The $error variable inside the function is not the $error variable you used outside. Take a look at Variable scope. — Aioros
– Aioros, Commented Apr 17, 2020 at 18:51

0stone0 · Accepted Answer · 2020-04-17 18:56:08Z

1

function addError($message) {
    $error .= "<br>" . $message;
}

The error variable only exist in the function's scope.

You could pass the error variable as a reference to the function, described with the & sign.

$error = "Begin:";

function addError(&$error, $message) {
    $error .= "<br>" . $message;
}

addError($error, "message1");
addError($error, "message2");

echo $error;

Test online!

On other option would be defining and changing a global variable.

answered Apr 17, 2020 at 18:56

0stone0

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