creating a new csv file with open() in specific directory

Question

My script creates a new csv file based on the date. It default saves the file the the local directory. Any idea how i can save it to a specific folder? Thx

    with open('record ' + str(current) + '.csv', 'a', newline='') as f:

rdas · Accepted Answer · 2020-05-04 04:14:13Z

1

The simplest way would be to add to the open functions path argument like so:

with open(folder_path + '/' + 'record ' + str(current) + '.csv', 'a', newline='') as f:

Assuming that folder_path holds a path to the specified folder like '/home/users/you/somefolder'

But I would suggest looking into using PathLib for path creation & manipulation

answered May 4, 2020 at 4:14

rdas

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dobleD · Accepted Answer · 2020-05-04 04:23:52Z

0

the file parameter in the open function is the path to such file. By indicating only the filename it's assumed as a file on the actual directory, so for writing it anywhere on your drive (as long as you have permissions) you should use full path

with open('/tmp/record ' + str(current) + '.csv', 'a', newline='') as f:

answered May 4, 2020 at 4:23

dobleD

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