how to find replace value with whitespace using sed in a bash script

Question

I have values in a file like this ' value-to-remove '(without the ' characters). I want to use sed to run through the file and replace the values including the space before and after. I am running this via a bash script. How can I do this?

The sed command I'm using at the moment replaces the values but leaves behind the two spaces.

sed -i 's/ '$value' / /g' test.conf

In script I have

sed -i -e 's/\s'$DOMAIN'-'$SITE'\s/\s/g' gitosis.conf

echoed as

sed -i -e s/\sffff.com-eeee\s/\s/g test.conf

Not working though.

btw, you should show your input and the wanted output.

clt60
– clt60

2011-06-05 16:19:38 +00:00
Commented Jun 5, 2011 at 16:19 — clt60
– clt60, Commented Jun 5, 2011 at 16:19

clt60 · Accepted Answer · 2011-06-05 16:17:35Z

2

IMHO your sed does not know '\s', so use [ \t], and use double quotes, otherwise your variables will not expand. e.g.:

sed -i -e "s/[ \t]'$DOMAIN'-'$SITE'[ \t]/ /g" gitosis.conf

edited Jun 5, 2011 at 16:17

answered Jun 5, 2011 at 13:05

clt60

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Eric Fortis · Accepted Answer · 2011-06-04 22:32:57Z

0

Let me know if this is what you need

echo 'Some values to remove value-to-remove and more' | sed -e 's/\svalue-to-remove\s/CHANGED/g'

output: Some values to removeCHANGEDand more

answered Jun 4, 2011 at 22:32

Eric Fortis

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