Substituting class name by variable in PHP

Question

Since which version of PHP is it possible to use the following:

$class::method()->something($val);

I need to use this but in 5.2.11 I get a T_PAMAAYIM_whatever error, and I just wanted to determine whether it's version related or bad coding.

If it's version related, what's a valid alternative?

Thank you.

Markus Hedlund · Accepted Answer · 2011-06-08 09:02:13Z

5

I think it's a PHP 5.3 feature. You should be able to call_user_func(array($class, $method), $val); in "any" version.

answered Jun 8, 2011 at 9:02

Markus Hedlund

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Seldaek · Accepted Answer · 2011-06-08 09:05:43Z

0

This is indeed a PHP5.3 feature. For now use call_user_func(array('Class', 'method'), $arg), and in the future PHP5.4 will even make it possible to do:

$callback = array('Class', 'method');
$callback($arg);

answered Jun 8, 2011 at 9:05

Seldaek

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Community · Accepted Answer · 2020-06-20 09:12:55Z

0

Added in PHP 5.3. From the release notes:

New features

Dynamic access to static methods is now possible.

http://php.net/manual/en/migration53.new-features.php

edited Jun 20, 2020 at 9:12

CommunityBot

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answered Jun 8, 2011 at 9:04

Emil Ivanov

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