How to Implement the function, which returnes index of tuple in the list with maximum sum of elements?

Question

I need an index of the element with the max sum inside of it, but what I done is only found the maximun inside the tuple in a listm instead of fining the index. Could you please help.

def max_sum_index(tuples):  
   
    # YOUR CODE HERE
    maxi = 0
  
    # traversal in the lists 
    for x in tuples: 
        sum = 0 
        # traversal in tuples in list 
        for y in x: 
            sum+= y      
        maxi = max(sum, maxi)  
          
    return maxi

print(max_sum_index([(10, 20), (40, 32), (30, 25)]))
#72

Tadhg McDonald-Jensen · Accepted Answer · 2020-07-17 16:56:48Z

2

to keep track of indices you may want to use enumerate

for i,x in enumerate(tuples):

then to keep track of index you need a variable for the highest sum and the index of that sum:

maxi = 0
max_val = 0

If you find an element that has a sum higher than max_val then that becomes the new max, along with it's index

    if sum > max_val:
        max_val = sum
        maxi = i

So you'd have something like:

def max_sum_index(tuples):  
   
    maxi = 0
    max_val = 0
  
    # traversal in the lists 
    for i,x in enumerate(tuples): 
        sum = 0 
        # traversal in tuples in list 
        for y in x: 
            sum+= y
        if sum > max_val:
            max_val = sum
            maxi = i 
          
    return maxi

print(max_sum_index([(10, 20), (40, 32), (30, 25)]))

answered Jul 17, 2020 at 16:56

Tadhg McDonald-Jensen

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Vishal Singh · Accepted Answer · 2020-07-17 17:05:40Z

2

sample = [(10, 20), (40, 32), (30, 25)]

index = sample.index(max(sample, key=sum))
print(index)

Output: 1

edited Jul 17, 2020 at 17:05

answered Jul 17, 2020 at 17:00

Vishal Singh

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1 Comment

alani Over a year ago

Or just key=sum. I don't see the benefit of lambda x:sum(x).

user120242 · Accepted Answer · 2020-07-17 16:57:42Z

1

uses a tuple with sum as first element to get maximum and include original tuple
index is the second element of the tuple, original tuple is the third element:

print(max((sum(x),i,x) for i,x in enumerate([(10, 20), (40, 32), (30, 25)])))
print('index: ', max((sum(x),i,x) for i,x in enumerate([(10, 20), (40, 32), (30, 25)]))[1])

edited Jul 17, 2020 at 16:57

answered Jul 17, 2020 at 16:56

user120242

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Comments

DaveIdito · Accepted Answer · 2020-07-17 17:00:58Z

0

You can use the list max function over your tuple.

max_index = max(enumerate([(10, 20), (40, 32), (30, 25)]), 
                key=lambda x: x[1][0]+x[1][1])[0]

print(max_index) #outputs 1 in this case

answered Jul 17, 2020 at 17:00

DaveIdito

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