Ruby regex to capture part of content between two strings

Question

With ruby gsub(), in string <code>balabala or blank \n another balabala or blank</code>, replacing all \n inside <code>...</code> block into <br>, but do nothing to the content outside <code>...</code>.

I tried /<code>.*(\\n?).*<\/code>/ but not working:

html = '<pre>do \n nothing<code>line \n break</code></pre>'

html = html.gsub(/<code>.*(\\n?).*<\/code>/) { "<br>" }

print html

# actual result: <pre>do \n nothing<br></pre>

# expect result: <pre>do \n nothing<code>line <br> break</code></pre>

Ryszard Czech · Accepted Answer · 2020-08-10 20:19:07Z

3

Match all substrings between <code> and </code> and replace all \n with <br> in those matches only:

html = html.gsub(/<code>.*?<\/code>/m) { $~[0].gsub('\n', '<br>') }

answered Aug 10, 2020 at 20:19

Ryszard Czech

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