How to create a zip archive in Python without creating files on file system?

Question

One easy way is to create a directory and populate it with files. Then archive and compress that directory into a zip file called, say, file.zip. But this approach is needless since my files are in memory already, and needing to save them to disk is excessive.

Is it possible that I create the directory structure right in memory, without saving the unzipped files/directories? So that I end up saving only the final file.zip (without the intermediate stage of saving files/directories on file system)?

Possible duplicate of stackoverflow.com/questions/2463770/… — S4rt-H4K
– S4rt-H4K, Commented Aug 25, 2020 at 21:21
@S4rt-H4K I don't think it says how to add a directory structure to it. E.g. add a folder/directory to it. Thoughts? — caveman
– caveman, Commented Aug 26, 2020 at 9:45
Just 1 directory. Or maybe multiple. Not quite sure about their number yet. — caveman
– caveman, Commented Aug 26, 2020 at 11:44

Martim · Accepted Answer · 2022-06-06 15:32:38Z

2

You can use zipfile:

from zipfile import ZipFile

with ZipFile("file.zip", "w") as zip_file:
    zip_file.writestr("root/file.json", json.dumps(data))
    zip_file.writestr("README.txt", "hello world")

edited Jun 6, 2022 at 15:32

answered May 24, 2022 at 4:54

Martim

1,16611 silver badges14 bronze badges

Sign up to request clarification or add additional context in comments.

1 Comment

Alexandra Espichán Over a year ago

This worked for me, but there is a typo: in the import Zipfile should be ZipFile (with a capital F)

Collectives™ on Stack Overflow

How to create a zip archive in Python without creating files on file system?

1 Answer 1

1 Comment

Your Answer

Linked

Hot Network Questions

Collectives™ on Stack Overflow

1 Answer 1

1 Comment

Your Answer

Sign up or log in

Post as a guest

Linked

Related