execute a php script on click of a html button

Question

I have a PHP code which does bunch of things so to keep things simple I have removed the unnecessary code from it.

In the below if block I need to create a pop up window with that $message on it and it should have ok and cancel button on it. Once I click ok button I need to execute some other php code in the same file if possible (or it can be another PHP file as well) and if I click cancel button then it should not do anything.

Below is my test.php file-

<?PHP
    // ..... some other code

    if (!isset($_SESSION['admin'])) {
        $text = "hello world";
        // create a pop up window with $message on it along with "ok" and "cancel" button
        echo "<script type='text/javascript'>confirm('$text');</script>";
    }

    // ..... some other code
?>

I can have either JS modal, or an HTML/CSS modal anything works as long as I can have some actions on ok and cancel button. Is this possible to do? I tried looking around but not able to figure it out on how to do this.

Update:

Below is my updated hello.php file where I used Oliver suggestion. I tried with below code where I have a javascript function secondUser but it shows popup as Sad :( - invalid session once I click ok button.

<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.11.2/jquery.min.js" type="text/javascript"></script>
<script>
function secondUser() {
    $.post( "ajax/test.php", function( data ) {
        if (data.success) {
            alert(data.message);
        } else {
            alert("Sad :( - invalid session");
        }
    });
}
</script>

<?PHP
    // ..... some other code

    if (!isset($_SESSION['admin'])) {
        $text = "hello world";
        // create a pop up window with $message on it along with "ok" and "cancel" button
        echo "<script type='text/javascript'>if (confirm('$text')) { secondUser(); };</script>";
    }

    // ..... some other code
?>

Now I am not able to figure it out what is wrong in my above code? I just want to execute my test.php using ajax in my other php file.

so you make an Ajax call or submit a form or navigate to a link. — epascarello
– epascarello, Commented Sep 8, 2020 at 1:25
a codeblock in the same file? probably not, but in another php file you could, just put a simple ternay on the confirm and simply add a location.href pointing to it. if it's a post you'd need a form or make an xmlhttprequest using post. — Kevin
– Kevin, Commented Sep 8, 2020 at 1:25
@epascarello I am wondering if you can give an example how to do this ? — user1950349
– user1950349, Commented Sep 8, 2020 at 1:32
@user1950349 you mean a ternary? its just a shorthand if else confirm() ? redirect : '' — Kevin
– Kevin, Commented Sep 8, 2020 at 1:34
@kevin I meant to say if you can provide me an example in the fiddle 3v4l.org Little bit code will work. — user1950349
– user1950349, Commented Sep 8, 2020 at 1:42

Oliver Kucharzewski · Accepted Answer · 2020-09-09 23:26:37Z

1

You can use jQuery library to make a request using AJAX. First thing is registering the button.

<button id="cool-btn">My button</button>

Once you have the button running, you can add this script to the html or JS file.

<script>
$(document).ready(function() {
    $("#cool-btn").click(function(){
        attemptRequest();
    });
});
</script>

Now you need to create a function called attemptRequest which makes an AJAX request for you to your PHP form.

function attemptRequest() {
    $.post( "ajax/test.php", function( data ) {
      if (data.success) {
          alert(data.message);
      } else {
          alert("Sad :( - invalid session");
      }
    });
}

Then you need to do the session checking in your PHP script called test.php in the ajax folder and return the appropriate data.

 $data = new stdClass();
 $data->success = false;
 $data->message = "";
 if (isset($_SESSION['pageadmin'])) {
     $data->message = "hello world";
     $data->success = true;
 }
 
 return json_encode($data);

Hope thats helpful :)

edited Sep 9, 2020 at 23:26

answered Sep 9, 2020 at 23:21

Oliver Kucharzewski

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5 Comments

user1950349 Over a year ago

Hi Oliver, I tried your code and in the sources (inspect) section I am seeing the following code On clicking Ok button, it says Sad :( - invalid session and its not going inside second_user.php file although its going inside secondUser() javascript function. I am wondering what changes I need to make in the fiddle so that it goes inside second_user.php file.

Oliver Kucharzewski Over a year ago

Hi user (you should change your name :) ) Could you show me how your files are now laid out?

user1950349 Over a year ago

I created a fiddle already and it's the same setup I have. I just have only one php file (admin.php) and in that php file I have everything (php+js). I know its not a best practice but I will try to change the structure later. I also updated the question with what I have tried.

user1950349 Over a year ago

I also updated my question with the details of what I tried.

Oliver Kucharzewski Over a year ago

Hi @user1950349 for this example could you please separate the PHP and JS/HTML files accordingly? I will gladly teach you to do it in one file in another question once we get the basics working. Apologies for the late response, ironically i usually am on stackoverflow on working days :)

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