Python beginner issue in dictionary

Question

      def myDict(key1, value1, key2, value2, value3, key3):
         # Write your code here
           a={key1:value1}
           print(a)
           a[key2]=value2
           print(a)
           a[key1]=value3
           print(a)
           a[key3]
           print(a)

      if __name__ == '__main__':
        key1 = 'name'
        value1 = 'rajesh'
        key2 = 'age'
        value2 = '21'
        value3 = 'vignesh'
        key3 = 'age'
        mydct = myDict(key1, value1, key2, value2, value3, key3)
        print(mydct if type(mydct) == dict else "Return a dictionary")

The driver function was pre-defined. The expected output is:

    {'name': 'rajesh'}
    {'name': 'rajesh', 'age': '21'}
    {'name': 'vignesh', 'age': '21'}
    {'name': 'vignesh'}

but i'm getting as :

    {'name': 'rajesh'}
    {'name': 'rajesh', 'age': '21'}
    {'name': 'vignesh', 'age': '21'}
    {'name': 'vignesh'}
    Return a dictionary

What mistake I'm doing?

myDict does not return a value. Make sure you understand what return does, and that print has nothing to do with it. — Karl Knechtel
– Karl Knechtel, Commented Sep 14, 2020 at 6:30

Tom Karzes · Accepted Answer · 2020-09-14 06:33:09Z

3

Add the following to the bottom of myDict:

    return a

Without it, myDict implicitly returns None, which is what you're seeing.

answered Sep 14, 2020 at 6:33

Tom Karzes

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Comments

alkesh Miyani · Accepted Answer · 2021-03-13 15:36:56Z

2

You missed these two lines:

    del a[key3]
    return a

Here is the complete logic:

def myDict(key1, value1, key2, value2, value3, key3):
        a={key1:value1}
        print(a)
        a[key2]=value2
        print(a)
        a[key1]=value3
        print(a)
        del a[key3]
        return a

edited Mar 13, 2021 at 15:36

answered Mar 13, 2021 at 12:00

alkesh Miyani

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1 Comment

Chris Over a year ago

Welcome to Stack Overflow. Code dumps without any explanation are rarely helpful. Stack Overflow is about learning, not providing snippets to blindly copy and paste. Please edit your question and explain how it works better than what the OP provided. See How to Answer.

KokoEfraim · Accepted Answer · 2020-09-14 06:48:58Z

Just add return a at the last line of def function. I tried it and it got what you want. As said, if you don't put a return statement at the end of a function, you get a NoneType object, which is then it not recognize your mydct object as a dictionary, instead print the else statement, as you said beforehand above.

def myDict(key1, value1, key2, value2, value3, key3):
 # Write your code here
   a={key1:value1}
   print(a)
   a[key2]=value2
   print(a)
   a[key1]=value3
   print(a)
   a[key3]
   print(a)
   return a

if __name__ == '__main__':
    key1 = 'name'
    value1 = 'rajesh'
    key2 = 'age'
    value2 = '21'
    value3 = 'vignesh'
    key3 = 'age'
    mydct = myDict(key1, value1, key2, value2, value3, key3)
    print(mydct if type(mydct) == dict else "Return a dictionary")

Ruli · Accepted Answer · 2021-02-11 11:30:11Z

-1

You what to change last statement to

Del a[key3]
Return a

It will give correct output.

edited Feb 11, 2021 at 11:30

Ruli

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answered Feb 11, 2021 at 9:16

Lakshmi Deepak

1

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