I've tried the following methods but none would work on Linux
from win32.win32api import GetSystemMetrics
print(GetSystemMetrics(0), GetSystemMetrics(1))
from ctypes import windll
info = windll.user32
print(info.GetSystemMetrics(0), info.GetSystemMetrics(1))
A solution using xlib:
import Xlib.display
display = Xlib.display.Display()
screen = display.screen()
print(screen.height_in_pixels, screen.width_in_pixels)
Try using tkinter, like:
from tkinter import *
root = Tk()
root.withdraw()
height,width = root.winfo_screenheight(),root.winfo_screenwidth()
print(height,width)
mainloop()?The following link had a good answer https://www.blog.pythonlibrary.org/2015/08/18/getting-your-screen-resolution-with-python/
I had to modify the last line to make it run in Python 3.
import subprocess
cmd = ['xrandr']
cmd2 = ['grep', '*']
p = subprocess.Popen(cmd, stdout=subprocess.PIPE)
p2 = subprocess.Popen(cmd2, stdin=p.stdout, stdout=subprocess.PIPE)
p.stdout.close()
resolution_string, junk = p2.communicate()
resolution = resolution_string.split()[0]
width, height = resolution.split(b'x')
xwininfo -root and look for the -geometry line (or indeed, the Width and Height)
from tkinter import *androot = Tk()androot.withdraw()androot.winfo_screenheight()androot.winfo_screenwidth()tkinter, it would be worth posting an answer. I posted one usingxlibbut that is not in the standard library, so obviously if there is something withtkinter, that would be an advantage. But it would be good if there is a way in tkinter that does not involve opening a new window (even if only temporarily).tkinterneeds a window, but try my answer out?