I'm trying to loop through numbers from -6 to 38, and output the odd numbers into an array. I don't know how to store the output into an array.
for (int i = -6; i<38; i++){
if (i%2!=0){
**output to array**
}
}
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Does this answer your question? Add element into array javaImtiazeA– ImtiazeA2020-10-14 04:57:48 +00:00Commented Oct 14, 2020 at 4:57
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1But what is your problem? Dont you know how to create an array, or how to compute the size it will need upfront? And note: this is really super basic stuff. Any good book (even the bad ones) explain to you how to create arrays. Please understand that this community isnt meant as replacement for you sitting down and doing that learning thing first.GhostCat– GhostCat2020-10-14 05:18:51 +00:00Commented Oct 14, 2020 at 5:18
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2 Answers
Because we are not able to know how many the number of the odd numbers is, so you can use IntStream to fix this issue if your java version is 8 or above.
int[] array = IntStream.range(-6, 38).filter(x -> x % 2 != 0).toArray();
Or you can use ArrayList
List<Integer> list = new ArrayList<>();
for (int i = -6; i < 38; i++) {
if (i % 2 != 0) {
list.add(i);
}
}
Comments
As the number to elements in array can not be always defined in advance. You can create a list and then convert that to array as below:
List<Integer> oddNumbers = new ArrayList<>();
for (int i = -6; i<38; i++){
if (i%2!=0){
oddNumbers.add(i);
}
}
Integer[] result = oddNumbers.toArray(new Integer[oddNumbers.size()]);
1 Comment
GhostCat
What makes you think that getting the size is the OP's problem?!