11

Consider the following struct:

struct Vector4D
{
   union
   {
      double components[4];
      struct { double x, y, z, t; } Endpoint;
   };
};

It seems to me that I have seen something similar in WinApi's IPAddress struct. The idea is to give me the possibility to use the array components both by index and by name, for example:

Vector4D v;
v.components[2] = 3.0;
ASSERT(v.Endpoint.z == 3.0) //let's ignore precision issues for now

In the C++ standard there is a guarantee that there will be no "empty" space at the beginning of a POD-struct, that is, the element x will be situated right in the beginnig of the Endpoint struct. Good so far. But I don't seem to find any guarantees that there will be no empty space or padding, if you will, between x and y, or y and z, etc. I haven't checked out the C99 standard though.

The problem is that if there is an empty space between Endpoint struct elements, then the idea will not work.

Questions:

  1. Am I right that there indeed is no guarantee that this will work either in C or C++.

  2. Will this practically work on any known implementation? In other words, do you know of any implementation where this doesn't work?

  3. Is there any standard(I mean not compiler-specific) way to express the same idea? Maybe the C++0x alignment features might help?

By the way, this isn't something I am doing in production code, don't worry, just curious. Thanks in advance.

4
  • This may be relevant: stackoverflow.com/questions/6272768. Commented Jun 23, 2011 at 10:16
  • I've just submitted gcc.gnu.org/bugzilla/show_bug.cgi?id=49514 Commented Jun 23, 2011 at 10:52
  • @Johannes: The idea of having references seems very dangerous to me, because the references will allow modifying the components of a const Vector4D object... No? Commented Jun 23, 2011 at 11:32
  • 1
    @Armed yes. a price to pay. and a good argument for the .z() way of doing things. Commented Jun 23, 2011 at 11:36

4 Answers 4

5
  1. yes
  2. depends on the alignment needs of the architecture and the compilers strategy
  3. no, but you could make a object wrapper (but you will end up with .z() instead of just .z)

Most compilers should support squashing a structure using a pragma or an attribute. #pragma pack for example.

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Comments

4

You can circumvent any memory alignment issues by having references to each element of the array, as long as you declare the array before the references in the class to ensure they point to valid data. Having said that I doubt alignment would be an issue with doubles, but could be for other types (float on 64bit arch perhaps?)

#include <iostream>
using namespace std;

struct Vector4D
{
    Vector4D() : components(), x(components[0]), y(components[1]), z(components[2]), t(components[3]) { }

    double components[4];

    double& x;
    double& y;
    double& z;
    double& t;
};

int main()
{
    Vector4D v;

    v.components[0] = 3.0;
    v.components[1] = 1.0;
    v.components[2] = 4.0;
    v.components[3] = 15.0;

    cout << v.x << endl;
    cout << v.y << endl;
    cout << v.z << endl;
    cout << v.t << endl;
}

Hope this helps.

5 Comments

I thought of this too, but it has a MAJOR drawback. When I take a const Vector4D, the components will be const, but I'll be able to change them through references. This is very very bad
You can always work around this C++ish issue using a smarter proxy that propagate const-ness.
@Matt, This makes me wonder about reference types that propagate constness, when using a special declaration specifier. Like, for a constant v, that v.x would have type double const. Would such a language feature make sense?
@Johannes: I am afraid it would only further bloat the language. Personally I would favor constness propagation by default, but this is the "functional" view of constness, while C++ is ingrained with the "technical" aspect.
And now the vector structure is twice as large.
2

When it comes to the standard, there are two problems with it:

  • It is unspecified what happens when writing to an element in a union and reading from another, see the C standard 6.2.6.1 and K.1
  • The standard does not guarantee the layout of the struct match that of the layout of the array, see the C standard 6.7.2.1.10 for details.

Having said this, in practice this will work on normal compilers. In fact, this kind of code is widely spread and is often used to reinterpret values of one type into values of another type.

2 Comments

To which C standard are you referring? C90 or C99?
I'm referring to the C99 standard.
0

Padding bytes will not cause an issue as all variables are of type double. The compiler will treat Vector4D as a double array. That means, v.Endpoint.z is essentially the same as v[2].

8 Comments

Do you mean practically or you also mean that the standard mandates my code to work correctly?
Are you sure? I don't see a problem with double having 6 bytes.
@Let_Me_Be How will 6 byte doubles with 2 byte padding in between break this code?
@Vijay Any padding will break the code. Arrays don't have padding.
@Let_Me_Be Vector4D is essentially an array of doubles. v.Endpoint.z will be compiled to v + 2.
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