For example I have GolDeNSanDyWateRyBeaChSand and I need to find how many times the word sand appears.
text = input()
text = text.lower()
count = 0
if "sand" in text:
count += 1
print(count)
But the problem is that there is 2 sand in this string and when it found the first one it stops. Im a beginner in the programming.
You can simply use the str.count() method to count how many times a string appears in another string.
text = input()
text = text.lower()
count = text.count("sand")
To find every occurrence of a string pattern inside another string s, even nested occurrences, do the following:
s = "sandsandssands" # your string here
pattern = "sands" # your pattern here
pos = -1
end_of_string = False
while not end_of_string:
pos = s.find(pattern, pos+1)
print(pos)
end_of_string = (pos == -1)
0
4
9
-1
Extending the solution offered by the OP.
The idea is to use find and move to towards the end of the string.
It is clear that count can be used here and the solution below is for educational purpose.
text = 'GolDeNSanDyWateRyBeaChSand'
word = 'sand'
ltext = text.lower()
offset = 0
counter = 0
while True:
idx = ltext.find(word, offset)
if idx == -1:
break
else:
counter += 1
offset = idx + len(word)
print(f'The word {word} was found {counter} times')
output
The word sand was found 2 times
