I'm trying to get all results of jq query in a array in bash, but it gives me all results in the first array element. Could you help me? I would like to having every result in one array element
bash-4.2$ try=$(tm run jobs:status::get -s "tm=serverA&work=*&status=Failed" | $PATH_API/jq -r '.statuses[].name // empty')
bash-4.2$ echo $try
job_B job_C
bash-4.2$ echo "${#try[@]}"
1
bash-4.2$
If the status names are sufficiently uncomplicated, you could add an extra pair of parentheses:
try=($(tm run ....))
(Consider also invoking jq without the -r option.)
Otherwise, you could consider using readarray, or other techniques for initializing bash arrays.
read -r -d '' -a try < <(tm run ... && printf '\0') -- even has a compelling advantage over the modern readarray approach insofar as it passes a nonzero exit status through (by emitting the trailing NUL, which causes read to return nonzero if the pipeline returned nonzero).
variable=$(command)creates a string variable, not an array.declare -p tryinstead ofecho $trywill provide a more unambiguous readout of the variable's value. With your current value it should emitdeclare -- try="job_B job_C"; with a real array it would bedeclare -a try=( [0]=job_B [1]=job_C )