Extract values from list and concatenate it to a string [duplicate]

Question

I have a list which contains various company names I am trying to extract each item from the list and concatenate it to a string. Here is how i do it:

stock = ['TATACHEM', 'SNOWMAN']
for element in stock:
    z1='NSE:'+element

The Issue I face over here is that when I see z1 it contains only last element of the list concatenated with the string 'NSE' and the resulting output is:

NSE:SNOWMAN

However when I print all the element of the list it gives me all the elements. That is when I use:

for element in stock:
    print(element)

It gives me a list of both the elements in the list:

TATACHEM
SNOWMAN

How do I modify my code above so as to get the following output:

NSE:SNOWMAN
NSE:TATACHEM

You assign to z1. z1 can only hold a single value, so yes, the latter assignment overrides all previous assignments. Did you mean to create a new list into which you put those new strings? — deceze
– deceze ♦, Commented Dec 9, 2020 at 7:13

Keldan Chapman · Accepted Answer · 2020-12-09 07:21:22Z

3

You could use z1 = "NSE: " + "\nNSE: ".join(stock)

Edit: If you want z1 as a list, then you could use list comprehension:

z1 = ["NSE:" + i for i in stock]

edited Dec 9, 2020 at 7:21

answered Dec 9, 2020 at 7:14

Keldan Chapman

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