Is there a built-in function for getting the size of a file object in bytes? I see some people do something like this:
def getSize(fileobject):
fileobject.seek(0,2) # move the cursor to the end of the file
size = fileobject.tell()
return size
file = open('myfile.bin', 'rb')
print getSize(file)
But from my experience with Python, it has a lot of helper functions so I'm guessing maybe there is one built-in.
Use os.path.getsize(path) which will
Return the size, in bytes, of path. Raise
OSErrorif the file does not exist or is inaccessible.
import os
os.path.getsize('C:\\Python27\\Lib\\genericpath.py')
Or use os.stat(path).st_size
import os
os.stat('C:\\Python27\\Lib\\genericpath.py').st_size
Or use Path(path).stat().st_size (Python 3.4+)
from pathlib import Path
Path('C:\\Python27\\Lib\\genericpath.py').stat().st_size
%timeit on all the files in a given directory and found os.stat to be marginally faster (~6%).
os.path.getsize() does nothing else than calling os.stat().st_size.os.path.getsize(path)
Return the size, in bytes, of path. Raise os.error if the file does not exist or is inaccessible.
You may use os.stat() function, which is a wrapper of system call stat():
import os
def getSize(filename):
st = os.stat(filename)
return st.st_size
Try
os.path.getsize(filename)
It should return the size of a file, reported by os.stat().
You can use os.stat(path) call
st_size attribute of the object you get back from that to get the file size.
Path('./doc.txt').stat().st_size