TypeScript typing: assigning an argument-less function to a function parameter which has arguments [duplicate]

I came across unexpected behaviour in TypeScript, and would like to understand the typing system better through this example.

Illustrating the example, we define a main function with a parameter which takes in a function with two arguments. We pass in a function which takes in no arguments as the default.

function noop(): void {
  console.log("I still work!");
}

function main(cb: (a: number, b: string) => void = noop) {
  cb(0, "0");
}

main();

Console:

I still work!

My expectation is that the linter would complain that noop takes in no arguments. So why does this behaviour still work?

(I was originally using export default (...args any[]): any => {} as my noop function from therealemjy/noop-ts, which adds to my confusion: if ...args is needed in the package, why does my simpler argument-less noop achieve the same thing?!)