In requests library, if you need to execute
curl http://www.example.com/file.xlsx
The command is
response = requests.get('http://www.example.com/file.xlsx')
What If I want to execute the command with -O option?
curl http://www.example.com/file.xlsx -O
How do I achieve that?
There's no explicit "-O" = write to the same filename.
You if you need that, you can store the url in a variable
and use several ways of getting it. A lazy way is using rpartition('/')[2] on
the url string.
The rest of the code to quickly save the result is here:
import requests
from pathlib import Path
response = requests.get('http://www.example.com/file.xlsx')
Path('file.xlsx').write_bytes(response.content)
# or if you want to have the file name extracted use this less readable line
# Path(response.url.rpartition('/')[2]).write_bytes(response.content)
To achieve the use case of CURL's -O option in Python, you have to write few lines of code like,
import requests
r = requests.get('https://your.url.com/path')
with open('path.txt','w') as fd:
fd.write(r.text)
r.content instead of the r.text.I'm not sure requests supports a flag for this purpose. However, you can try doing something like:
from pathlib import Path
p = Path('http://www.example.com/file.xlsx')
r = requests.get(str(p))
Path(p.name).write_bytes(r.content)
Ooption or the requests equivalent of curl commandcurl http://www.example.com/file.xlsx -Ousing python