Please check code bellow:
https://codepen.io/Whity/pen/XWNVqvP?editors=1010;
Result:
[">20Y", {…}]
["5Y", {…}]
["6M", {…}]
["7Y", {…}]
["10Y", {…}]
["14D", {…}]
["15Y", {…}]
["20Y", {…}]
I need to have the element with the '>' symbol last, not first. How can I achieve that?
When using dictionaries doesn't really make sense to sort by keys, but here you go.
var data = {
"6M": {},
"14D": {},
"7Y": {},
"10Y": {},
"5Y": {},
"15Y": {},
">20Y": {},
"20Y": {}
};
function sortOnKeys(dict) {
var sorted = [];
for(var key in dict) {
sorted[sorted.length] = key;
}
sorted.sort(function(a,b) {
return a.replace(/^\W+/, 'z').localeCompare(b.replace(/^\W+/, 'z'));
});
var tempDict = {};
for(var i = 0; i < sorted.length; i++) {
tempDict[sorted[i]] = dict[sorted[i]];
}
return tempDict;
}
data = sortOnKeys(data);
console.log(data)
Keep it simple. notes are in the comments section in the example.
var obj = {
"6M": {},
"14D": {},
"7Y": {},
"10Y": {},
"5Y": {},
"15Y": {},
">20Y": {},
"20Y": {}
};
//Object.keys() returns an array whose elements are strings corresponding to the enumerable properties found directly upon object
//sort() method sorts the elements of an array in place and returns the sorted array. The default sort order is ascending, built upon converting the elements into strings, then comparing their sequences of UTF-16 code units values.
//reduce() method executes a reducer function (that you provide) on each element of the array, resulting in single output value.
console.log(Object.keys(obj).sort().reduce(function (result, key) {
result[key] = obj[key];
return result;
}, {}));
//just throwing in another variant if you really need numbers to be in right sort order. This becuase above sort does string comparision. What if comaprision had to be on numaeric base.
console.log(Object.keys(obj).sort((a, b) => a.localeCompare(b, 'en', { numeric: true })));
You could sort by numbers and if a comparison sign is available, then take for the same numerical value the delta of both offsets, which reflects the order of comparison, see my answer with comparison signs.
To get numerical value, just get the digits from the string.
const
data = [[">20Y", {}], ["5Y", {}], ["6M", {}], ["7Y", {}], ["10Y", {}], ["14D", {}], ["15Y", {}], ["20Y", {}]];
data.sort(([a], [b]) => {
function getV(s) {
return {
value: s.match(/\d+/),
offset: { '<': -2, '<=': -1, null: 0, '>=': 1, '>': 2 }[s.match(/[<>]={0,1}(?=\s*\d)/)]
};
}
var aa = getV(a),
bb = getV(b);
return aa.value - bb.value || aa.offset - bb.offset;
});
console.log(data);.as-console-wrapper { max-height: 100% !important; top: 0; }