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I would like to apply the same background color to cells that have for each PEOPLE instance the name and the related name. I have tried to df.style.applymap, it does not return an error but it does not seem to work. Anyone has any ideas why? Thank you.

   clrs = list(mcolors.CSS4_COLORS.keys())
   for k in range(len(PEOPLE)):
        if PEOPLE[k].attribute == 'child':
            df1_data = [PEOPLE[k].name, PEOPLE[k].related]
    
            df.style.applymap([lambda x: 'background-color: yellow' if x in df1_data else 'background-color: red'])
    

    df.to_excel('styledz.xlsx', engine='openpyxl')
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  • applymap accepts a function, not a list Commented Mar 22, 2021 at 22:10
  • also df.style is the object, not df, so you need to use df.style.to_excel. And also you need not create multiple df.style instances. Basically there is a lot wrong with your code Commented Mar 22, 2021 at 22:12
  • Thank you for your answer. If i cannot put df.style in a loop, how can i color multiple cells with different colors? Commented Mar 26, 2021 at 8:26
  • have you tried reading the user guide for Styling at pandas documentation. it has many examples. Commented Mar 26, 2021 at 11:08
  • @ChristinaJ If you find my answer helpful, I'd appreciate it if you accept it or upvote it! Commented Apr 7, 2021 at 14:23

2 Answers 2

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Here is some more info on df.style. Here I'm using some simple example because I don't have your data available:

import pandas as pd
import numpy as np

df = pd.DataFrame({'a': np.random.randint(0, 10, 10), 'b': np.random.randint(0, 10, 10), 'late': np.random.choice([0, 1], 10).astype(np.bool)})

def highlight_late(s):
    return ['background-color: red' if s['late'] else 'background-color: green' for s_ in s]
df = df.style.apply(highlight_late, axis=1)
df.to_excel('style.xlsx', engine='openpyxl')

Looks in the excel file like this:

enter image description here

For cell based coloring use:

def highlight_late(s):
    return ['background-color: red' if s_ else 'background-color: green' for s_ in s]


df = df.style.apply(highlight_late, subset=["late"], axis=1)

This gives you:

enter image description here

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4 Comments

Thank you for your answer. I would like to know how to color only certain cells with different colors not a whole axis.
@ChristinaJ I updated the answer to only use one cell for coloring
Thank u! One last comment, what if i want to color cell a[5] and b[2]. I mean what if they are not in the same column? Lets say a[5] and b[2] have the same string written to it.
apply([...], axis=1) works on the whole row, you can simply check in the function highlight_late for a keyword and skip the subset=["late"] in the apply
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Basically your solution will be a modification of the following:

df = DataFrame([['mark', 2], ['mike', 4], ['manny', 6]], columns=['name', 'attribute']) 
def style_row(row, people):
    output = Series("", index=row.index)
    if row["name"] in people:
        output['attribute'] = "background-color:red;"
    return output
styler = df.style.apply(style_row, axis=1, people=['mark', 'manny'])
styler
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