I have this string '=F*G'
I want to replace it to numbers to be '=6*7'
I have successfully managed to replace letters with number using this code
var string = '=F*G'
.toLowerCase().split('')
.filter(c => c >= 'a' & c <= 'z')
.map(c => c.charCodeAt(0) - 'a'.charCodeAt(0) + 1)
.join(' ')
console.log(string);but this code removes the '=' and '*' I need help keeping them in string after replacing letters with numbers
You can use String#replace with a callback replacer function. This replacer function can use String#charCodeAt() to produce an ordinal value for each alphabetical character in the string.
console.log("=F*G".replace(/[A-Z]/g, m => m.charCodeAt() - 64));Use [a-zA-Z] or the i flag if you want to match both cases and generate different numbers per upper/lower letter. If you want to normalize both cases to produce the same digits, call String#toUpperCase() first before applying the provided code above (or use toLowerCase() as you're doing and change the ordinal subtraction value accordingly -- it doesn't matter).
You can't filter the characters, or they won't be in the output to union back together. Try this.
var string = '=F*G'
.toLowerCase().split('')
.map(c => {
if (c >= 'a' && c <= 'z') {
return c.charCodeAt(0) - 'a'.charCodeAt(0) + 1
}
return c;
})
.join('')
console.log(string);
