q = []
num = ["1","2","3","4","5","6","7","8","9","0"]
while True:
dat = float(input("Enter Name: "))
if dat == "*":
print(q.pop(0))
if dat in num :
break
else:
q.append(dat)
#the program only terminates when inputted 0 to 9 numbers but I want it to terminate if any numbers are inputted.
Use .isdigit(). Try in this way-
q = []
#num = ["1","2","3","4","5","6","7","8","9","0"]
while True:
dat = input("Enter Name: ")
if dat == "*":
print(q.pop(0))
if dat.isdigit() :
break
else:
q.append(dat)
Instead of checking if dat is a digit, should then check if any of its characters is a digit:
q = []
somedigit = False
while True:
dat = input("Enter Name: ")
if dat == "*":
print(q.pop(0))
for element in dat:
if element.isdigit():
somedigit = True
break
if somedigit == True:
break
else:
q.append(dat)
Other way is to check the function isalpha:
q = []
while True:
dat = input("Enter Name: ")
if dat == "*":
print(q.pop(0))
if not dat.isalpha():
break
else:
q.append(dat)
