if statement in dropdown menu with condition in php

Question

Hi what i would like to do in my dropdown is to put a condition if($formdata[0]['Phase']==1){ to show only the option values 0,1 and 2 in dropdown but if($formdata[0]['Phase']==3){ to show only the option values 0,3 and 4 in dropdown here is my code

<?php } ?>
                                        
<div class="form-group col-md-12 col-xs-12">
<label><?php echo $t[$tmpvalues[0]['Lang']]['poles'];?></label>
<label>NUMBER OF POLES</label> 
<select class="form-control el-text-box" name="polesi" id="polesi" onchange="this.form.submit()">
                                                
<option value="0" <?php echo $formdata[0]['polesi'] == "0" ? "selected" : ""; ?> >None</option>        
<option value="1" <?php echo $formdata[0]['polesi'] == "1" ? "selected" : ""; ?> >1</option>
<option value="2" <?php echo $formdata[0]['polesi'] == "2" ? "selected" : ""; ?> >2</option>
<option value="3" <?php echo $formdata[0]['polesi'] == "3" ? "selected" : ""; ?> >3</option>
<option value="4" <?php echo $formdata[0]['polesi'] == "4" ? "selected" : ""; ?> >4</option>
</select>                    
</div>

OK, what have you tried so far? That should be quite straightforward to do. What about if the value is a different value than 1 or 3? Display all of them? — droopsnoot
– droopsnoot, Commented Apr 22, 2021 at 18:07

dev_mustafa · Accepted Answer · 2021-04-22 18:33:09Z

1

There are different ways

1st using if condition as below

<?php if($formdata[0]['Phase']==1){  ?>    
<option value="1" <?php echo $formdata[0]['polesi'] == "1" ? "selected" : ""; ?> >1</option>
<option value="2" <?php echo $formdata[0]['polesi'] == "2" ? "selected" : ""; ?> >2</option>
<?php } ?>


<?php if ($formdata[0]['Phase']==3) { ?>

<option value="3" <?php echo $formdata[0]['polesi'] == "3" ? "selected" : ""; ?> >3</option>
<option value="4" <?php echo $formdata[0]['polesi'] == "4" ? "selected" : ""; ?> >4</option>
<?php } ?>

2nd way is using CSS

<option value="3" style="<?php echo $formdata[0]['Phase'] == "3" ? "display:block" : "display:none"; ?>"3</option>

same for other options according to your condition

edited Apr 22, 2021 at 18:33

answered Apr 22, 2021 at 18:11

dev_mustafa

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7 Comments

Pavlos Christoforou Over a year ago

second is not working as it doesnt show any values on dropdown menu and 1st has a problem, i am not sure if i am doing something wrong

dev_mustafa Over a year ago

Can you share what the error is? Also, I have updated the second answer it was 'polesi' it should have been 'Phase' (this is incomplete you need to do for others option accordingly)

Pavlos Christoforou Over a year ago

1st option the if...... it makes the <option value WHITE

Pavlos Christoforou Over a year ago

1st now works with some modification thank you so much

Pavlos Christoforou Over a year ago

``` <div class="form-group col-sm-6 col-xs-12"> <label for="d13"><?php echo $t[$tmpvalues[0]['Lang']]['d13'];?></label> <select class="form-control el-text-box" name="d13" onchange="this.form.submit()"> <?php for ($j=0; $j<sizeof($ahk); $j++){ $selected="";if($ahk[$j]==$formdata[0]['d13']){$selected="selected";} ?> <option value="<?php echo $ahk[$j];?>" <?php echo $selected; ?>><?php echo $ahk[$j];?></option> <?php } ?> </select> </div>

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