Django - How to display specific content in a template

Question

Django newbie question - I need to display a specific entry in a template. So far I have not been able to get this to work. I have the following code:

model:

class BasicPage(models.Model):
    title = models.CharField(max_length=200)
    body = HTMLField()

    def __str__(self):
        return self.title

view:

class TermsPageView(TemplateView):
    model = BasicPage
    template_name = 'terms.html'

    def get_queryset(self):
        body = BasicPage.objects.filter(id=1)
        return body

template:

{% block content %} 

<h1>{{ body.title }}</h1>

{% endblock content %}

May.D · Accepted Answer · 2021-08-09 23:18:04Z

1

We would need more information to solve this issue, but I guess that, as get_queryset returns a QuerySet which is an iterable, to display body in you template you need to use a for loop :

{% block content %} 
{% for i in body %}
<h1>{{ i.title }}</h1>
{% endfor %}
{% endblock content %}

Anyway, using TemplateView to return a single item filter(id=1) seems to indicate that you need to deep digger in documentation, this kind of view aims to be generic, not return a single item with unique ID.

answered Aug 9, 2021 at 23:18

May.D

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Comments

Brian Destura · Accepted Answer · 2021-08-10 00:48:49Z

0

To pass this object as a context, you need to use get_context_data:

class TermsPageView(TemplateView):
    model = BasicPage
    template_name = 'terms.html'

    def get_context_data(self, **kwargs):
        context = super().get_context_data(**kwargs)
        context['body'] = BasicPage.objects.get(id=1)
        return context

Note that this is using get so you will only get one object. But if you really want to use a queryset (if you use filter), then you need to iterate through the list as @May.D has indicated.

answered Aug 10, 2021 at 0:48

Brian Destura

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1 Comment

Finn Over a year ago

This probably makes the most sense since I only want to return one object.

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