Assign data to a four Dimensional Array at RunTime

Question

I have a four dimensional array for which I have a static set of values. But my problem is I want to fetch some data from api and have to put it into the four dimensional array during runtime. I am not sure how to do this. Any slightest idea will be appreciated. Here is my sample which shows my static definition of my four dimensional array.

static final String listdesc[][][][] =
{
    { // grey
      {  // lightgray
        { "grey", "grey only" },
        { "lightgrey","#D3D3D3" },
        { "dimgrey","#696969" }
      },
      {  // darkgray
        { "grey", "darkgrey" },
        { "sgi grey 92","#EAEAEA" }
      }
    },
    { // blue
      {  // lightblue
        { "blue", "lightblue" },
        { "dodgerblue 2","#1C86EE" }
      },
      {  // darkblue
        { "blue", "darkblue" },
        { "steelblue 2","#5CACEE" },
        { "powderblue","#B0E0E6" }
      }
    },
    { // yellow
      {  // lightyellow
        { "yellow", "lightyellow" },
        { "yellow 1","#FFFF00" },
        { "gold 1","#FFD700" }
      },
      {  // darkyellow
        { "yellow", "darkyellow" },
        { "darkgoldenrod 1","#FFB90F" }
      }
    },
    { // red
      {  // lightred
        { "red", "lightred" },
        { "indianred 1","#FF6A6A" }
      },
      {  // darkred
        { "red", "darkred" },
        { "firebrick 1","#FF3030" },
        { "maroon","#800000" }
      },

    }
};

denis.solonenko · Accepted Answer · 2011-08-02 05:06:52Z

1

This is called primitive obsession code smell. You should replace 4d string array with a proper data structure and API to create it:

ColorsData data = new ColorsData();
ColorSection section = data.addSection("gray");
section.setLightColors(
        "grey only",
        Color.create("lightgray", "#D3D3D3"),
        Color.create("dimgray", "#696969"))
section.setDarkColors(
        "darkgray",
        Color.create("sgi grey 92", "#EAEAEA")
);
section = data.addSection("blue")
...

edited Aug 2, 2011 at 5:06

answered Aug 2, 2011 at 4:44

denis.solonenko

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3 Comments

alphazero Over a year ago

That sounds like a designer fragrance )

denis.solonenko Over a year ago

@alphazero what do you mean? :)

alphazero Over a year ago

")" (That is my Russian smilie + your primitive obsession code smell reminded of a Calvin Klein ad))

Honza Zidek · Accepted Answer · 2015-07-01 15:53:29Z

0

Fetch data in AsyncTask/background and assign it in postExecute do this.

listdesc[][][][];
for (int i=0; i<listdesc.length; i++) {
    for (int j=0; j<listdesc[i].length; j++) {
        for (int k=0; k<listdesc[i][j].length; k++) {
            for (int m=0; m<listdesc[i][j][k].length; m++) {
                // populate with values
            }
        }
    }
}

edited Jul 1, 2015 at 15:53

Honza Zidek

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answered Aug 2, 2011 at 4:45

ngesh

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Comments

Tanmoy · Accepted Answer · 2015-07-01 15:34:15Z

0

public class Source {

public static void main(String[] args)
{

    Random r = new Random();
    int [][][][] a = new int[r.nextInt(10)+1][][][];

    for(int i=0;i<a.length;i++)
    {
        a[i] = new int [(r.nextInt(5)+1)][][];
        for(int j=0;j<a[i].length;j++)
        {
            a[i][j] = new int[(r.nextInt(5)+1)][];
            for(int k=0;k<a[i][j].length;k++)
            {
                a[i][j][k] = new int [(r.nextInt(5)+1)];
                for(int l=0;l<a[i][j][k].length;l++)
                {
                    a[i][j][k][l] = r.nextInt(101)+100;
                }
            }
        }
    }
    for(int i=0;i<a.length;i++)
    {
        System.out.println("3D #"+i);
        for(int j=0;j<a[i].length;j++)
        {
            System.out.println("2D #"+j);
            for(int k=0;k<a[i][j].length;k++)
            {
                System.out.println("1D #"+k);
                for(int l=0;l<a[i][j][k].length;l++)
                {
                    System.out.print(a[i][j][k][l] + " ");
                }
                System.out.println();
            }
            System.out.println();
        }
        System.out.println();
    }
    System.out.println();

}

answered Jul 1, 2015 at 15:34

Tanmoy

1

1 Comment

Cthulhu Over a year ago

Hi, welcome to StackOverflow. Please don't just dump code, explain your train of thought so we can better understand your answer. Thanks.

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