How do I load in string values into dictionary with keys?

Question

In Python 3 I've created an empty dictionary with the following keys:

default_value = ''

sq = dict.fromkeys(['Num','ID','Cognome','Data','altezza','V6','spec_role','V8','Nome','Ruolo','nick','trasf','straniero','pict','V15','V16','V17'],default_value)

I don't know how to load values from a string like this sequentially:

line = '1   LUC-TOR Tortuga 10/13/1991              LUC-TOR Luca    2   Tortuga         33524.7 '

to obtain:

mydict = { 
    "Num": 1,
    "ID": LUC-TOR,
    "Cognome": Tortuga,
    "Data": 10/13/1991
    "altezza":
    "V6": 
    "spec_role":
    "V8":
    "Nome": Luca
    "Ruolo": 2
    "nick": Tortuga
    "trasf":
    "straniero":
    "pict":
    "V15":
    "V16":
    "V17": 33524.7
}

What is the best pythonic way to do it?

I've forgot to say that the string is tab separated. For that I can use the string.split method as I know. — LucaTortuga
– LucaTortuga, Commented Sep 9, 2021 at 15:41

Barmar · Accepted Answer · 2021-09-09 15:43:23Z

3

Use split() to split the string into a list of values. Then you can combine it with the list of keys.

keys = ['Num','ID','Cognome','Data','altezza','V6','spec_role','V8','Nome','Ruolo','nick','trasf','straniero','pict','V15','V16','V17']
my_dict = dict(zip(keys, line.split('\t')))

answered Sep 9, 2021 at 15:43

Barmar

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Open AI - Opting Out · Accepted Answer · 2021-09-09 15:49:58Z

2

You could use zip:

keys = ['Num','ID','Cognome','Data','altezza','V6','spec_role','V8','Nome','Ruolo','nick','trasf','straniero','pict','V15','V16','V17']

values = line.split('\t')

mydict = dict(zip(keys, values))

zip produces a sequence of tuple pairs, e.g. ('Num', '1'), ('ID', 'LUC-TOR'), ...

If you wanted you could also have a list of types to convert the values to:

types = [int, str, str, date, ...]

mydict = {key: _type(value)
          for key, value, _type in zip(keys, values, types)}

edited Sep 9, 2021 at 15:49

answered Sep 9, 2021 at 15:43

Open AI - Opting Out

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1 Comment

LucaTortuga Over a year ago

Thanks a lot I didn't know the zip function.

Praveen K M · Accepted Answer · 2021-09-09 15:46:17Z

0

use zip() and split():

keys = ['Num','ID','Cognome','Data','altezza','V6','spec_role','V8','Nome','Ruolo','nick','trasf','straniero','pict','V15','V16','V17']
mydict = dict(zip(keys, line.split('\t')))

answered Sep 9, 2021 at 15:46

Praveen K M

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Yuri Molodyko · Accepted Answer · 2021-09-09 15:52:00Z

0

If you need to convert your line to array, there is my func:

def convert_to_array(value):
    result_line = ''
    white_space_prev=False
    for el in line:
        if el!=' ':
            if white_space_prev:
                result_line+=' '+el
            else:
                result_line+=el
            white_space_prev=False
        else:
            white_space_prev=True
    return result_line.split(' ')
line = '1    LUC-TOR Tortuga 10/13/1991              LUC-TOR Luca    2   Tortuga         33524.7 '
print(convert_to_array(line))

result:

['1', 'LUC-TOR', 'Tortuga', '10/13/1991', 'LUC-TOR', 'Luca', '2', 'Tortuga', '33524.7']

answered Sep 9, 2021 at 15:52

Yuri Molodyko

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