Bash crashes when executing script that defines a function with the same as an existing command

Question

I am very new to bash. All I want to do is run this nvvp -vm /usr/lib64/jvm/jre-1.8.0/bin/java without having to remember the path at the end. I figured the instafix would be to just do this...

nvvp() {
    nvvp -vm /usr/lib64/jvm/jre-1.8.0/bin/java
}

Then I could just call nvvp and it would boot up Nvidia's Visual Profiler. But this just crashes my terminal.

Shellcheck automatically detects this and other common issues — that other guy
– that other guy, Commented Sep 19, 2021 at 17:40

Socowi · Accepted Answer · 2021-09-19 17:39:29Z

4

The redefinition of nvvp is global. Inside the function nvvp you execute that very same function, causing an infinite recursion. To call the actual binary instead of the function, use bash's command built-in:

nvvp() {
    command nvvp -vm /usr/lib64/jvm/jre-1.8.0/bin/java
}

edited Sep 19, 2021 at 17:39

answered Sep 19, 2021 at 16:33

Socowi

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Comments

John Goofy · Accepted Answer · 2021-09-19 16:26:30Z

3

It look's like a fork. Try out

another_name() {
nvvp -vm /usr/lib64/jvm/jre-1.8.0/bin/java
}

answered Sep 19, 2021 at 16:26

John Goofy

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1 Comment

chrisdottel Over a year ago

Ahh, that fixed it thanks!

markp-fuso · Accepted Answer · 2021-09-19 18:40:08Z

0

Another option would be to define an alias, eg:

alias nvvp='nvvp -vm /usr/lib64/jvm/jre-1.8.0/bin/java'

answered Sep 19, 2021 at 18:40

markp-fuso

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