count the output python

Question

I want to compare two lists: -CAGGTGGTGAT (my_list[0])

--CAGGTGTGAT (my_list[1])

And I want to find how many pairs I have (A-A, C-C, G-G, T-T) and how many mismatches. I have this code for the mismatches

for i in range(len(my_list[0])):
        if my_list[0][i-1]!=my_list[1][i-1]:
            print("mismatch")

How can i count how many mismatches are printed? I tried to use count, but it counts pairs and mismatches. I want to count only the mismatches that are printed.

Andrej Kesely · Accepted Answer · 2021-10-04 23:51:24Z

1

You can use sum() with zip() to count the mismatches:

mylist = ["-CAGGTGGTGAT", "--CAGGTGTGAT"]

mismatches = sum(a != b for a, b in zip(mylist[0], mylist[1]))
print(mismatches)

Prints:

answered Oct 4, 2021 at 23:51

Andrej Kesely

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3 Comments

anastasia Over a year ago

it returns the error 'Counter' object is not callable. I'm new to python so I don't really know what I can do.

Andrej Kesely Over a year ago

@anastasia You've probably assigned to name sum before. Don't use python builtin names as variable names.

anastasia Over a year ago

if i didn't assign sum before, what might be the problem?

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