How can I pull out the 2 numbers in-between Price Our:
and the following | from this string?
"Delivery: Price => 30.00 - 45.00 | Price Our: 1900.00 => 1800.00 | Delivery: Contact => 3 - 4 Days | "
I tried (Price Our:.*?(?=\|)) But thats the limit of my regex knowledge
You could use 2 capture groups:
\bPrice Our: (\d+(?:\.\d+)?) => (\d+(?:\.\d+)?) \|
The pattern matches:
\bPrice Our: A word boundary to prevent a partial match, then match Price Our: (\d+(?:\.\d+)?) Capture group 1, match a number with an optional decimal part=> Match literally(\d+(?:\.\d+)?) Capture group 2, match a number with an optional decimal part \| Match |const s = "Delivery: Price => 30.00 - 45.00 | Price Our: 1900.00 => 1800.00 | Delivery: Contact => 3 - 4 Days | ";
const regex = /\bPrice Our: (\d+(?:\.\d+)?) => (\d+(?:\.\d+)?) \|/;
const match = s.match(regex);
if (match) {
console.log(match[1]);
console.log(match[2]);
}In case the digits are at the end of the string, and there is no | following, you can account for that using an alternation to assert the end of the string:
\bPrice Our: (\d+(?:\.\d+)?) => (\d+(?:\.\d+)?)(?: \||$)
(\d*\.\d+)regex101 explanation:
const regex = /(\d*\.\d+)/gm;
const str = "Delivery: Contact => 3 - 4 Days | Price Our: 1900.00 => 1800.00 | Delivery: Contact => 3 - 4 Days | ";
const res = str.match(regex)
console.log(res)
Price our: to the following |