For example,
# foo.py
class Foo:
foo = "foo"
# main.py
from foo import Foo
f = Foo()
print(f.__file__) # doesn't work, but is there something that would?
(ideally)$: python3 main.py
/the/whole/path/to/foo.py
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2 Answers
inspect.getfile will do it for you.
Comments
Use inspect.
Demonstration when a class is not created in the same file and a class in the source file.
with open('foo_file.py','w') as f_out:
f_out.write("class Foo:\n\tfoo = \"foo\"")
import inspect
from foo_file import Foo
# Create a local class
class InThisFile:
pass
def main():
print(inspect.getfile(Foo))
print(inspect.getfile(InThisFile))
x = Foo()
# Path to the file for the instance of x
print(inspect.getfile(type(x)))
if __name__ == '__main__':
main()
Test results:
C:\Users\user\AppData\Roaming\JetBrains\PyCharm2021.3\scratches\foo_file.py
C:\Users\user\AppData\Roaming\JetBrains\PyCharm2021.3\scratches\scratch_22.py
C:\Users\user\AppData\Roaming\JetBrains\PyCharm2021.3\scratches\foo_file.py
5 Comments
Chris
Ah, I am looking for a way to get this from the object instantiation... And I screwed up the question
VPfB
@Chris, you can pass the
type(instance) to the getfile.Chris
Think if you add
.__class__ to the argument it will workChris
@VPfB lol same time
Carl_M
Modified and tested answer using ` print(inspect.getfile(type(x)))` to reflect the previous comments.