Convert iterable to list using streams [duplicate]

Question

I have a simple loop that adds elements from one list to another list. How can the same result be achieved using streams?

List<User> users = new ArrayList<>();
for(User user: userRepository.findAll()) {
    users.add(user);
}

The reason for doing so is because userRepository.findAll() returns Iterable<User>

@Olivier The only reason for using streams is to be better with them. — Kristjan
– Kristjan, Commented Mar 6, 2022 at 9:36
But it is not "better" with them. Streams are not automatically "better". And in this case, they are not. As you can see, a Stream-based solution is more complicated, and it won't be more efficient. — Stephen C
– Stephen C, Commented Mar 6, 2022 at 10:16

Krishna Majgaonkar · Accepted Answer · 2022-03-06 09:42:53Z

5

spliterator() converts Iterable in stream and then collect it as a List using collect()

List<User> users = 
  StreamSupport.stream(userRepository.findAll().spliterator(), false)
    .collect(Collectors.toList());

answered Mar 6, 2022 at 9:42

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