Filter for array of objects that contain all key value pairs of one object in another array of objects

Question

Given I have this array of objects:

    let array1 = [
        {id: 1, name: "Test Item 1", price: 100, type: 'item'},
        {id: 1, name: "Test Fee 1", price: 200, type: 'fee'},
        {id: 3, name: "Test 3", price: 300, type: 'item'},
    ]

Now i want to filter so I only have the objects where every key value of the following array match:

    let array2 = [
        {id: 1, type: "item"},
        {id: 3, type: "item"},
    ]

This should return array1[0] and array1[2]. My current solution has been this, but it wont work if array2 has multiple object keys to compare to:

array1.filter(row => {
    return array2.find(r => {
        return Object.entries(row).some(([key, value]) => r[key] === value);
    })
});

Does this answer your question? Comparing two arrays of objects, and exclude the elements who match values into new array in JS — stijnb1234
– stijnb1234, Commented Oct 21, 2022 at 14:39
Not really, as that does the inverse and it also filters by a hardcoded key (id), i need to filter by comparing to multiple key/value pairs. — xTheWolf
– xTheWolf, Commented Oct 21, 2022 at 14:40
@GrafiCode array1 should only return objects where each key/value of one of the objects in array2 match. So not only type is taken into consideration, but also id. (note theres two times the same id on array1 with a different type). I'm just bad at explaining :) — xTheWolf
– xTheWolf, Commented Oct 21, 2022 at 14:46
Do it the other way round: Object.entries(r).every(([key, value]) => row[key] === value). Get the entries of r and check if every value in second array is present in the row object — adiga
– adiga, Commented Oct 21, 2022 at 14:47
@adiga You're a hero. Such a simple solution after all. Works flawlessly, thanks! If you post it as an answer, I'll be glad to mark it as the accepted one. — xTheWolf
– xTheWolf, Commented Oct 21, 2022 at 14:52

bbbbbbbboat · Accepted Answer · 2022-10-21 14:52:31Z

2

array1.filter((row) =>
  array2.some((template) =>
    Object.keys(template).every((key) => template[key] === row[key])
  )
);

I think the answer in comment above is cleaner than mine.

answered Oct 21, 2022 at 14:52

bbbbbbbboat

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Comments

GrafiCode · Accepted Answer · 2022-10-21 14:54:47Z

1

In array1.filter() you can iterate all objects in array2 and compare keys using Object.keys()

let array1 = [
  {id: 1, name: "Test Item 1", price: 100, type: 'item'},
  {id: 1, name: "Test Fee 1", price: 200, type: 'fee'},
  {id: 3, name: "Test 3", price: 300, type: 'item'},
]

 let array2 = [
   {id: 1, type: "item"},
   {id: 3, type: "item"},
 ]

const res = array1.filter(row => {
  for (const obj of array2) {
    if (Object.keys(obj).every(k => obj[k] === row[k])) {
      return row
    }
  }
})

console.log(res)

answered Oct 21, 2022 at 14:54

GrafiCode

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Comments

A1exandr Belan · Accepted Answer · 2022-10-21 15:27:47Z

1

Lodash if you don't mind:

const array1 = [{id: 1, name: "Test Item 1", price: 100, type: 'item'},{id: 1, name: "Test Fee 1", price: 200, type: 'fee'},{id: 3, name: "Test 3", price: 300, type: 'item'}];
const array2 = [{id: 1, type: "item"},{id: 3, type: "item"}];

const fn = _.overSome(array2.map(_.matches));
const result = _.filter(array1, fn);

console.log(result);

.as-console-wrapper { max-height: 100% !important; top: 0 }

<script src="https://cdn.jsdelivr.net/npm/[email protected]/lodash.min.js"></script>

answered Oct 21, 2022 at 15:27

A1exandr Belan

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