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I have a csv file with below values, I am trying to replace the value "^@" using SED command but getting error message "Pattern not found".

Value:

^@#uiuiuiui^@
^@#uiuiuiui^@
^@#uiuiuiui^@
^@#uiuiuiui^@
^@#uiuiuiui^@

Attempt:

sed 's/^@/$/g' file.csv
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1 Answer 1

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You have to backslash the ^ char. In a regular expression, it means "starts with". It is an operator. Since you want to explicitly replace it, backslash it.

So:

sed 's/\^@/$/g' file.csv
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3 Comments

I tried the option but still it is not replacing the value. The same error mgs "Pattern not found" is displayed.
I put your sample content in a file and ran it, it works. Make sure your file has unix line feeds (dos2unix file.csv).
I am trying it in Mac.

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