Check for multiple values with JS include

Question

There is a function that checks the content of the url with window.location.href. If the URL contains a specific string it should return true:

const doesItContain = () => {
  const url = window.location.href;
  return url.includes('/items');
};

This works fine, if the url contains /items it returns true. The issue comes when it needs to check for multiple strings (multiple pages) and return true if one of them are present. For example:

const doesItContain = () => {
  const url = window.location.href;
  return url.includes('/items', '/users');
};

It returns true only for the first string in the list. Is there a way to check for both or more than one string?

user16540390 · Accepted Answer · 2023-02-05 19:36:28Z

2

String.prototype.includes expects one argument. The other arguments are ignored.

You can use some to iterate an array of strings and check if at least one element fullfils the condition:

const doesItContain = () => {
  const url = window.location.href;
  return ['/items', '/users'].some(el => url.includes(el));
};

answered Feb 5, 2023 at 19:36

user16540390

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Comments

Unmitigated · Accepted Answer · 2023-02-05 19:38:42Z

0

You can use a regular expression, separating each of the strings to check with |.

return /\/items|\/users/.test(url);

answered Feb 5, 2023 at 19:38

Unmitigated

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2 Comments

Youssef Hossam Over a year ago

can you provide a way to dynamically create the regex for different situations

Unmitigated Over a year ago

@YoussefHossam Yes, use the RegExp constructor.

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