php multidimensional array count dynamically

Question

I have two arrays $users and $find. I need count how many matches in $users if $find array would be changed.

$users = array(
    [
        'name' => 'Jim',
        'sname' => 'Carrey'
    ],
    [
        'name' => 'Michael',
        'sname' => 'Douglas'
    ],
    [
        'name' => 'Michael',
        'sname' => 'Jackson'
    ],
    [
        'name' => 'Michael',
        'sname' => 'Jordan'
    ]
);

Find array changed dynamically. It may be:

$find = array (
    'name' => array('Michael'),
    'sname' => array('Douglas', 'Jordan')
);

OR:

$find = array (
    'sname' => array('Carrey', 'Jordan')
);

I'm looking for a one-size-fits-all solution for for any values in $find array. Thanks!

I can count if I have static keys and values in $find array:

$result = array_filter($users, function($user) {
    return in_array($user['name'], ['Michael', 'Jim']) && in_array($user['sname'], ['Douglas', 'Jordan', 'Carrey']);
});
$count = count($result);
print_r($result);

But I don't understand how count if it should be dynamic keys and values in $find array.

Related: Filter array of associative arrays with a dynamic associative array where all elements must be matched and Dynamic multiple search filter in Multidimensional Array php and How to filter an array based on multiple selected values — mickmackusa
– mickmackusa ♦, Commented Feb 25, 2023 at 14:24

C3roe · Accepted Answer · 2023-02-14 10:01:03Z

0

If you want to deal with an unknown number of items in $find, then you will need to loop over them. The use keyword helps to "inject" $find into your callback function. In your loop, you can return false, if the in_array check for the current find item results in false, otherwise you return true after the loop.

$result = array_filter($users, function($user) use ($find) {
    foreach($find as $col => $values) {
        if(!in_array($user[$col], $values)) {
            return false;
        }
    }
    return true;
});

answered Feb 14, 2023 at 10:01

C3roe

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