Loop file items starting in defined index [duplicate]

Question

im triying to iterate a file and start the loop in the second item of the list.

file = open(filename, 'r', encoding='iso-8859-1')
for line in file:
   # here i want to start the for in the second row
    line = line.strip('\n')

Any tips?

I tried doing:

start_row = 2
end_row = 10
file = open(filename, 'r', encoding='iso-8859-1')
for line in file[start_row:end_row]:
   # here i want to start the for in the second row
    line = line.strip('\n')

But i cant index a IOTextWrapper.

RomanPerekhrest · Accepted Answer · 2023-09-22 10:27:45Z

1

Just skip the 1st record with next call and use context manager to cover file's open/close phases:

with open(filename, 'r', encoding='iso-8859-1') as f:
   next(f)
   for line in f:
       line = line.strip('\n')

answered Sep 22, 2023 at 10:27

RomanPerekhrest

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3 Comments

Alex Ribeiro Over a year ago

Why do you add next(f) before the for loop? I want to skip the first line.

with open(filename, 'r', encoding='iso-8859-1') as f:    for line in f:      if start_row > line:        next(line)      line = line.strip('\n')

RomanPerekhrest Over a year ago

@AlexRibeiro, nothing wrong there, cause f is iterator

Alex Ribeiro Over a year ago

Hey. Finally what i did was just use the continue like this:

start_row = 2 end_row = 10 count = 0 file = open(filename, 'r', encoding='iso-8859-1') for line in file:     count =count+1     if count < start_row or count > end_row:           continue     line = line.strip('\n')

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