Using command line argument to substitute a value in a .sh script [duplicate]

New bash user here, I'm trying to accomplish something simple but can't seem to figure it out

I want to run a script (curl.sh) using a command line argument that will change every time to supply a new IP to the .sh

So running:

~/Documents$ ./curl.sh 10.0.0.18

Would result in the following being run:

#!/bin/bash
curl 10.0.0.18 blablabla

and then running: ~/Documents$ ./curl.sh 10.0.0.19

Would change the .sh to run:

#!/bin/bash
curl 10.0.0.19 blablabla

I have tried setting variables with this article and arguments using sed in this article but must be getting the syntax wrong