I have a service that selects tasks from Redis using a Lua script. I can select up to 1000 tasks at a time. Every 250 milliseconds I will retrieve tasks, and there are several such modules in one service (each module is responsible for processing background tasks, conditionally 3 modules each will retrieve 1000 tasks. So I have a question, do I need to use ```sync.Pool`` for memory allocation and optimisation? Will it not cause other problems and will I be able to get a performance gain, since the tasks consist of 5-8 fields in the structure.
My code
var taskPool = sync.Pool{
New: func() interface{} {
// This will be overridden by the generic type T at runtime
var t interface{}
return &t
},
}
// bytePool is a sync.Pool for reusing []byte buffers for JSON unmarshaling.
var bytePool = sync.Pool{
New: func() interface{} {
return make([]byte, 0, 1024) // Initial capacity for typical JSON task size
},
}
var extractCommand = redis.NewScript(`
local key = KEYS[1]
local max_tasks = tonumber(ARGV[1])
local tasks = {}
for i = 1, max_tasks do
local task = redis.call('LPOP', key)
if not task then
break
end
table.insert(tasks, task)
end
return tasks
`)
const maxTask = 1000
type Fetcher[T any] struct {
rdb redis.UniversalClient
logger *zerolog.Logger
}
func (f *Fetcher[T]) Fetch(ctx context.Context, keys []string) ([]T, error) {
result, err := extractCommand.Run(ctx, f.rdb, keys, maxTask).Result()
if err != nil {
return nil, err
}
tasks := make([]T, 0)
if results, ok := result.([]interface{}); ok && len(results) > 0 {
for _, task := range results {
outPtr := taskPool.Get()
out, ok := outPtr.(*T)
if !ok {
out = new(T)
}
if tasksVal, valOk := task.(string); valOk {
buf := bytePool.Get().([]byte)
buf = buf[:0]
buf = append(buf, tasksVal...)
if err = json.Unmarshal(buf, out); err != nil {
taskPool.Put(out)
bytePool.Put(buf)
continue
}
tasks = append(tasks, *out)
taskPool.Put(out)
bytePool.Put(buf)
}
}
}
return tasks, nil
}
sync.Poolfor memory allocation and optimisation?» — No. You can but certainly are not required to. 2) «Will it not cause other problems» — No, it won't. Or, rather, it may make allocation a bit slower, but not necessarily; see below. 3) «and will I be able to get a performance gain, since the tasks consist of 5-8 fields in the structure.» — Not necessarily. One cannot say w/o actually profiling both cases. There do exist cases where some perf. hack solves an obvious problem but yours is not one of them. Possibly you will get some gain, but don't expect wonders.tasks = append(tasks, *out)appears to negate half of your efforts: you poolTs but then havetasksgrow to be at leastlen(results)(it can, and most probably will, allocate more than that internally) and then copy over bytes from theseTs. In this case, it's more idiomatic to preallocatetasksto hold exactlylen(results), then have an index totasksbe incremented on each iteration overresults(starting from 0) and then directly manipulate a task at that index instead ofappending. Say, if that index variable isi, you'd unmarshal to&tasks[i].