The name 'AppUsageException' isn't a type and can't be used in an on-catch clause

Question

my code ->

import 'package:app_usage/app_usage.dart';
    
class ScreenTimeService {
  Future<List<AppUsageInfo>> getUsageStats() async {
    try {
      DateTime endDate = DateTime.now();
      DateTime startDate = endDate.subtract(const Duration(days: 1));
          List<AppUsageInfo> infoList = await AppUsage().getAppUsage(startDate, endDate);
          infoList.removeWhere((app) => app.usage.inSeconds == 0);
          return infoList;
        } on AppUsageException catch (exception) {
          print(exception);
          // You should guide the user to the settings here
          // AppUsage().openUsageSettings();
          return [];
        }
      }
    }

The full codebase it logically and syntax correct but I'm getting this error

The name 'AppUsageException' isn't a type and can't be used in an on-catch clause. Try correcting the name to match an existing class.

Munsif Ali · Accepted Answer · 2025-06-27 12:00:35Z

0

I searched through the package code and AppUsageException is not a defined type. So, on the home page of the package, it might be a mistake. In all the source code, there is no definition for AppUsageException.

So, try removing it and handle exceptions like this:

import 'package:app_usage/app_usage.dart';

class ScreenTimeService {
  Future<List<AppUsageInfo>> getUsageStats() async {
    try {
      DateTime endDate = DateTime.now();
      DateTime startDate = endDate.subtract(const Duration(days: 1));
      List<AppUsageInfo> infoList = await AppUsage().getAppUsage(startDate, endDate);
      infoList.removeWhere((app) => app.usage.inSeconds == 0);
      return infoList;
    } catch (e) {
      print(e);
      return [];
    }
  }
}

This approach is also used in the example code provided by the package.

answered Jun 27 at 12:00

Munsif Ali

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