how to print lambda expression

Question

I have two (many) lambdas:

myFoo = lambda x,y: x + y
mySpecFoo = lambda x: myFoo(x, 1)

I want to print resulting expression for mySpecFoo. smth like

x = var('x')
print(mySpecFoo(x))

and I want to see in output:

lambda x: x + 1

Do you know how to do this? Thank you!

Sven Marnach · Accepted Answer · 2011-11-05 15:36:05Z

3

This is called "symbolic evaluation", and you need some external library to do this, for example SymPy:

>>> import sympy
>>> myFoo = lambda x,y: x + y
>>> mySpecFoo = lambda x: myFoo(x, 1)
>>> x = sympy.var("x")
>>> print mySpecFoo(x) 
1 + x

answered Nov 5, 2011 at 15:29

Sven Marnach

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1 Comment

thanks, Sage is cool but the shell for windows is still under dev :(