SimpleDateFormat ParseException: Unparseable date Error

Question

I'm parsing this date format from XML: "2011-12-06T07:41:14.016+00:00", and I'm getting this error:

*W/System.err(574): java.text.ParseException: Unparseable date: "2011-12-06T07:41:14.016+00:00"

I'm certain it's the formatting statement I'm using, but I can't figure out what it SHOULD be.

Here's the statement I'm using:

SimpleDateFormat sdf = new SimpleDateFormat("yyyy-MM-dd'T'hh:mm:ss.SSSZ:ss");

I get how to create a format for this part: "2011-12-06T07:41:14....", it's this other part :=> ".016+00:00" that's throwing me for a loop.

I've looked for answers here already: Android SimpleDateFormat Page, and here Oracle SimpleDateFormat Page, but I fear I'm missing something fundamental....

What is the proper format statement for that particular date format?

You should check out this related question stackoverflow.com/questions/909022/… — skynet
– skynet, Commented Dec 6, 2011 at 23:46

Neil Essy · Accepted Answer · 2011-12-06 23:48:26Z

5

The "Z" pattern matches +0000 and not +00:00 so if you remove the last ":" before you parse then it will work.

SimpleDateFormat sdf = new SimpleDateFormat("yyyy-MM-dd'T'hh:mm:ss.SSSZ");
try {
  Date myDate = sdf.parse( "2011-12-06T07:41:14.016+00:00".replaceAll( "([0-9\\-T]+:[0-9]{2}:[0-9.+]+):([0-9]{2})", "$1$2" ) );
  System.out.println( myDate );
} catch (ParseException e) {
  e.printStackTrace();
}

answered Dec 6, 2011 at 23:48

Neil Essy

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2 Comments

user85421 Jul 23 at 14:37

parsing a time without AM/PM using 12 hour format (hh) is not the best idea

Joop Eggen Jul 23 at 14:39

There still is a small secundary bug from the original question: hh (12 hours) should be HH (24 hours) otherwise you will get wrong PM times.

Sid Malani · Accepted Answer · 2011-12-06 23:42:14Z

2

"yyyy-MM-dd'T'HH:mm:ss.SSSZ"    2001-07-04T12:08:56.235-0700

The :ss at the end looks incorrect

answered Dec 6, 2011 at 23:42

Sid Malani

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Comments

Community · Accepted Answer · 2017-05-23 10:29:00Z

2

As one of the answers in the question I linked shows, you can use

String string = "2011-12-06T07:41:14.016+00:00";
Calendar cal = DatatypeConverter.parseDateTime(string);

What's the best way to parse an XML dateTime in Java?

edited May 23, 2017 at 10:29

CommunityBot

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answered Dec 6, 2011 at 23:49

skynet

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