I have a php variable "echo $id". Now I want to use the $_POST method to post the variable. I just want to know how to do this for a variable because $_POST[$id] does not work?
6 Answers
I think you are misunderstanding a basic concept here.
The $_POST super global is used to receive input (in the form of a POST request) from the user. While it is possible to set variables in it, you shouldn't.
Comments
Your question does not make sense. If you have an HTML form:
<form action="" method="post">
<input type="text" name="something" />
<input type="submit" value="Submit" />
</form>
Then you get the variable $_POST['something'] with whatever the user typed in the text box.
On its own, $_POST is just a variable like any other. You can assign to it $_POST['test'] = 123;, you can delete from it unset($_POST['test']);, you can even make it something other than an array $_POST = "Hello, world";, it just happens to be pre-populated with form data, if any.
answered Dec 17, 2011 at 13:36
Niet the Dark Absol
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Comments
With the method $_POST you must be posting to something.
My suggestion to you is to create a form, then have the form going to the file you wish to post to:
So something like this:
echo '<form action = "fileToPostTo.php" method = "post">
<input type = "text" hidden value = "'.$id.'" />
</form>';
And then submit the form when the document loads through jquery or javascript.
Comments
You can do it by $_POST['id'] = $id (then You will have it in $_POST['id'] variable (but You shouldn't do it :P).
Or You can send $id by form. Like example:
<form action="/pageToPOST.php" method="post">
<input type="text" value="<?=$id ?>" name="id" />
<input type="submit" name="" value="submit it!" />
</form>
And You'll have $_POST['id'] on http://yourdomainname.com/pageToPOST.php page
Comments
you can get and pass the value without page load and form.
<input type="text" name="something" id="something" />
<input type="button" value="ok" onclick="value();"/>
function value()
{
var something=$("#something").val();
var dataparam="oper=show&something="+something;
$.ajax({
type:"post",
url:"yourphpname.pnp",//this is very important.
data:dataparam,
success:function(data)
{
alert(data);
}
});
}
$oper =(isset( $_REQUEST['oper'])) ? $_REQUEST['oper'] : '';
if($oper == "show" and $oper != '')
{
$something=$_REQUEST['something']
echo $something;
}
Comments
what you want to do is assign a value submitted to your script using the POST method, to your $id variable. Something like:
$id = $_POST['id'];
Comments
posting the variable? $_POST gets data out of a form into a variable. And it's not a method,$_POSTis a variable itself.