how to extract some criteria from this page http://www.zigwheels.com/api/zigtvApi.php?method=data&module=News§ion=News
and filter this ( content_id , thumbnail, summary , headline , image) to display them as rss feeds in my android GUI
2 Answers
The output from that URL looks like a JSON feed. You can easily parse JSON data in Android using the JsonObject - see this tutorial for a comprehensive example.
A better (and probably easier) solution would be to use Google Gson and extract the object that way. I've written a full (compilable) program you can use as an example here.
1 Comment
Ti7a
hey there check this this is the simplist p-xr.com/… '''''''''''''' but the problem is with ,,,JSONArray earthquakes = json.getJSONArray(“earthquakes”); ,,,,,,,,,,,,,, in my case as this link ,,,,,zigwheels.com/api/…,,,,,, it is not array so i will return the object directly so how will it be made how to loop or to get all info from page ???
You are receiving a JSONArray from that page. You should create some objects from that JSONArray which will be later displayed in a ListView. For retrieving objects from that feed you could use Json or Gson as @Marvin Pinto suggested, or you could also have a look at my ObjectFactory project, which is a very simple and easy to use parser. It can simply create your objects from a json or xml feed, and you could also use it asynchronously.
After you fetch your objects, with your desired option, you can create a ListAdapter and use it to display your objects in your ListView.
1 Comment
Ti7a
hey there check this this is the simplist p-xr.com/… '''''''''''''' but the problem is with ,,,JSONArray earthquakes = json.getJSONArray(“earthquakes”); ,,,,,,,,,,,,,, in my case as this link ,,,,,zigwheels.com/api/…,,,,,, it is not array so i will return the object directly so how will it be made how to loop or to get all info from page ???