class constructor not processing when called from inside another class constructor

Question

I have a ready made class X

class X
{
   private $pA;
   function __construct($id=0)
   {
      $pA=new myClass($id);
   }
}

class myClass
{
   private $id;
   function __construct($id=0)
   {
      echo 'constructing....';
   }
}

But there is no echo output the class construction stops at the new operator.

sorry there is () after myclass I mistook

Did you add <?php and ?> on your files ? Your code works like a charme :-) — Luc M
– Luc M, Commented Feb 23, 2012 at 2:20

Basti · Accepted Answer · 2012-02-23 01:59:11Z

2

Parse error: parse error, expecting `'{'' in test.php on line 11

change

class myClass()

to

class myClass

and actually do new X(); and it will work as expected.

you might also want to set error_reporting = E_ALL and display_errors = 1 in your php.ini when developing or debugging code to see whats wrong.

answered Feb 23, 2012 at 1:59

Basti

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Comments

summea · Accepted Answer · 2012-02-23 01:59:47Z

0

It worked for me when I took out the () after myClass() like this:

class myClass
{
    private $id;
    function __construct($id=0)
    {
        echo 'constructing....';
    }
}

answered Feb 23, 2012 at 1:59

summea

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1 Comment

summea Over a year ago

And like @Shredder said, it's a good idea to use $this-> when referring to a class member variable.

Nick Rolando · Accepted Answer · 2012-02-23 02:04:08Z

0

Have you actually tried creating an object of type X?

Also, you address class members using $this

$this->pA = new myClass($id);

And the error that @Basti pointed out should be addressed as well.

GL~

edited Feb 23, 2012 at 2:04

answered Feb 23, 2012 at 1:57

Nick Rolando

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2 Comments

Nick Rolando Over a year ago

Did you try creating an X object? $myX = new X();

Nick Rolando Over a year ago

@Wexas I copy+pasted the code you have above, and added $myX = new X(); after it (all within <?php ... ?> tags of course) and it works fine.

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